Like terms are terms with the identical variable part
3x² and −7x² are like terms. 3x² and 3x³ are not, and no amount of rearranging will make them so. Same variable, same exponent — both conditions, every time.
Addition collects like terms, and the licence to do it is the distributive law read backwards. Subtraction is the same operation after the minus sign has been distributed over every term — which is where the errors live.
Core ideas
There is only one new idea here, and it is not "add the numbers". It is the question of when you are allowed to.
3x² and −7x² are like terms. 3x² and 3x³ are not, and no amount of rearranging will make them so. Same variable, same exponent — both conditions, every time.
3x² + 5x² = (3 + 5)x² = 8x² because ab + ac = a(b + c) with a = x². You are not inventing a rule for polynomials; you are using the one rule arithmetic already gave you.
(A) − (B + C) is A − B − C. Missing the second sign flip is the most common single error in this course, and it produces an answer that looks entirely reasonable.
The material
Why like terms combine, why unlike terms cannot, and what subtraction really is.
Two terms are like terms when their variable parts are identical — the same variables raised to the same exponents. 5x²y and −2x²y are like terms; 5x²y and 5xy² are not.
The coefficients play no part in deciding. 100x³ and x³ are like terms; x³ and x² are not, however close the exponents look.
For any number a, b and any whole number n, axⁿ + bxⁿ = (a + b)xⁿ.
This is the distributive law ac + bc = (a + b)c with c = xⁿ. It is not a special rule about polynomials, and that is exactly why it is safe.
Turn the theorem around and you can see why x² + x³ cannot be collected: there is no common c to pull out other than x², and pulling that out gives x²(1 + x) — a product, not a shorter sum. It is a legitimate move, and it is factoring, which starts in “Factoring Out the Greatest Common Factor”. It just is not addition.
Subtracting a polynomial means adding its negative, and the negative of a polynomial has every sign flipped:
The left-hand form is the distributive law with −1: −1 · (x² − 5x − 2) = (−1)x² + (−1)(−5x) + (−1)(−2). Nothing is being remembered here; every sign is computed.
The safest habit is to write the negated polynomial out as its own line before adding anything. It costs one line and removes the error class entirely.
The degree of a sum is at most the larger of the two degrees. Usually it equals it — but if the leading terms cancel, the degree drops:
This is why “Polynomials, Degree and Standard Form” insisted that degree is read after combining. Addition can lower a degree; it can never raise one.
(3x³ − 5x + 2) + (x³ + 4x² − 5). The x³ terms give 4x³; there is only one x² term, 4x²; only one x term, −5x; the constants give 2 − 5 = −3. Result: 4x³ + 4x² − 5x − 3.
Interactive
Like terms, lined up by power
Method
For subtraction, step 1 is the whole battle.
Write −(…) out in full with every sign flipped, on its own line, before you collect anything. Then the problem is an addition and stays one.
Descending degree, both of them. Like terms then line up in columns and you can see at a glance which powers are present.
Take all the x³ terms, then all the x² terms, and so on. Working by power rather than left to right is what stops a term being used twice or skipped.
If the leading terms cancelled, the answer has a lower degree than either input. That is a legitimate result, not a mistake.
(4x² − 3x + 6) − (x² − 5x − 2), with the negation written out.
The two signs that flipped were on −5x and −2, and both became positive. Skipping step 1 and writing 4x² − 3x + 6 − x² − 5x − 2 gives 3x² − 8x + 4: a tidy-looking answer, and wrong in two places.
Check any result by substituting a number into the original and into the answer. At x = 1 the original is 7 − (−6) = 13, and the answer is 3 + 2 + 8 = 13. One substitution catches nearly every sign error.
For a faded subtraction, begin (3x³ − 2x + 4) − (−x³ + 5x − 6) with the supplied negation +x³ − 5x + 6. Collect the three powers and check at x = 1. You should obtain 4x³ − 7x + 10; the original and answer both give 7 at x = 1. A middle term of +3x means the 5x was not negated.
You should be able to take a difference of two quartics and get every sign right first time, because you write the negation on its own line rather than doing it in your head. Substituting x = 1 into both the question and your answer should be automatic.
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