Start by assuming the hypothesis
You are not proving q. You are proving that q follows from p, so p is yours to use from the first line.
The default technique: to prove p → q, assume p and reason forward to q. Most of the difficulty is not logical but expository — a proof is a piece of writing whose job is to convince a careful reader.
Core ideas
Three things make a direct proof work: the right starting assumption, justified steps, and a reader who can follow them.
You are not proving q. You are proving that q follows from p, so p is yours to use from the first line.
"n is even" is not a fact to be contemplated but a statement to be replaced: n = 2k for some integer k. Most direct proofs are definition unfolding plus algebra.
"Let n be an even integer" licenses a conclusion about every even integer. "Let n = 4" does not.
The material
The method, then the standards a written proof is held to.
Almost every theorem is a universally quantified conditional: ∀x (P(x) → Q(x)). A direct proof takes an arbitrary x satisfying P, and derives Q(x) by a chain of justified steps.
To prove p → q, assume p and derive q through a sequence of steps, each justified by a definition, a previously proved result, or a rule of inference.
For all integers m and n, if m and n are odd then m + n is even.
Let m and n be arbitrary odd integers. By definition of odd, there are integers j and k with m = 2j + 1 and n = 2k + 1.
Then m + n = (2j + 1) + (2k + 1) = 2j + 2k + 2 = 2(j + k + 1).
Since j + k + 1 is an integer, m + n is twice an integer, which is the definition of even. As m and n were arbitrary odd integers, the claim holds for all of them.
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Notice how much of that is definition management. "Odd" was replaced by 2j + 1 immediately, the algebra was routine, and the final step recognised 2(j + k + 1) as matching the definition of even. Two different letters j and k were used because m and n are different numbers — reusing one letter for both would have proved only the case m = n.
Two conventions worth adopting. Write in complete sentences — a proof is prose containing symbols, not a column of formulas. And distinguish the assumption you made from the conclusion you reached; confusing the two is how a proof silently becomes circular.
"Claim: if n² is even then n is even. Proof: n is even, so n = 2k, so n² = 4k² is even." This proves the converse, having assumed the conclusion. It is the most common flawed proof in this course, and “Contraposition and Contradiction” gives the technique that handles the real claim.
When a direct proof stalls, that is information. Being unable to get from p to q forwards often means the natural route is backwards — through the contrapositive — which is “Contraposition and Contradiction”.
Interactive
Two of these statements are false
Method
The first two steps are where proofs are won or lost.
Including quantifiers and domain. If you cannot state it precisely you cannot prove it, and half of all failed attempts end here.
Replace "even", "divides", "rational" by what they mean. Symbols can be manipulated; adjectives cannot.
Keep the target in view. If a step is not moving toward it, it is probably not the step to take.
The last line must match the definition of the conclusion. 2(j + k + 1) is even because it is twice an integer — say so.
a | b means "a divides b": there is an integer k with b = ak.
Two separate letters j and k are essential: the two factors have no reason to be equal. Using k twice would prove only the special case b = aj and c = bj, which is a different and much weaker theorem.
Prove: if n is an odd integer then n² is odd. Then hand it to someone and watch for the place they hesitate. That place is where a justification is missing, whether or not the mathematics is right.
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