The form exposes what you need
In y = mx + b, the coefficient of x is the slope and the constant is the y-intercept. No work is required to extract them — which is the entire reason for rearranging into this shape.
Solving a linear equation for y puts the slope and the y-intercept in plain sight, which makes graphing immediate and comparison between two lines a matter of looking.
Core ideas
The same line has many equations. This one is arranged so that the two numbers you need in order to draw it are simply there to be read.
In y = mx + b, the coefficient of x is the slope and the constant is the y-intercept. No work is required to extract them — which is the entire reason for rearranging into this shape.
Whatever the equation looks like, the procedure is Linear Equations and Inequalities's: undo the additions, then undo the multiplication. The only new demand is finishing in exactly the shape mx + b.
Vertical lines are the sole exception, since they cannot be solved for y at all. That exception is not an inconvenience; it is a signal, and “What a Function Is” explains what it signals.
The material
The rearrangement, the reading, and the graphing method it enables.
A non-vertical line written y = mx + b, where m is the slope and (0, b) is the y-intercept.
Why b is the y-intercept takes one substitution rather than memory: the y-intercept is where x = 0, and putting x = 0 into y = mx + b gives y = b. Why m is the slope takes two: at x = 0 the height is b, at x = 1 it is m + b, so a run of 1 produces a rise of m.
The work is Linear Equations and Inequalities's, applied to an equation that keeps x around as a passenger. Move every term that is not y to the other side, then divide by whatever multiplies y — dividing the whole side, every term:
The last step is where a term gets dropped. (-2x + 12)/3 is -(2/3)x + 4, not -(2/3)x + 12: the divisor applies to every term of the numerator. Checking against “Graphing a Linear Equation” settles it — the intercepts there were (0, 4) and (6, 0), and -(2/3)(6) + 4 = 0 confirms both.
−2y = −4x + 10, then dividing by −2 gives y = 2x − 5. Both signs change, because both terms are divided by a negative. Check with (3, 1): the original gives 12 − 2 = 10, and the new form gives 2(3) − 5 = 1.
Dividing by a negative is the reliable source of errors in this lesson. It changes the sign of every term it touches, and changing only the first is a mistake that leaves a plausible-looking equation behind. The check by substitution costs a few seconds and catches it.
Plot (0, b). Then use the slope as a set of instructions: write it as a fraction rise/run, move that run to the right and that rise up (down, if the slope is negative), and mark the point you land on. Two points, and the line is drawn.
Start at (0, 2). The slope −3/4 says: run 4 right, rise −3, meaning 3 down. That lands on (4, −1), and indeed −(3/4)(4) + 2 = −3 + 2 = −1.
A whole-number slope is a fraction too: m = 2 is 2/1, so the instruction is 1 right and 2 up. Forgetting the invisible denominator is what turns a slope of 2 into a step of 2 right and 2 up, which is a line of slope 1.
The form also makes comparison trivial, and that is what “Parallel and Perpendicular Lines” will use: two lines written this way can be checked for parallelism by looking at two coefficients, with no computation at all.
Interactive
Slope-intercept, point-slope and standard, derived separately
Method
Isolate y, then read the two numbers off.
If the equation has no y at all it is vertical, and this form does not exist for it. Say so rather than forcing it.
Add or subtract from both sides. The x-term goes to the right; the constant that was with y goes with it.
Every term, not just the first. If that coefficient is negative, expect every sign on the right to change.
The coefficient of x is m; the constant is b. Substitute any convenient x into both the original and the new equation and confirm the same y comes out.
Isolate y, extract the two numbers, then verify against the original equation.
Dividing −2y = −4x + 10 by −2 changes both signs on the right: −4x becomes +2x and +10 becomes −5. Changing one and not the other gives y = 2x + 5, which passes no substitution check at all.
The two verifications are different in kind. The first confirms the intercept is a genuine solution; the second confirms the two equations have the same solutions, which is what rearranging is supposed to preserve.
For a faded rearrangement, start −3x + 6y = 18 from the supplied line 6y = 3x + 18. Divide every term, identify m and b, make one slope step from the intercept, and verify that new point in the original equation.
Given five equations in mixed arrangements, including one with a negative y-coefficient and one horizontal, you should produce correct slope-intercept forms and sketch each from (0, b) and a slope step. “Parallel and Perpendicular Lines” compares lines in this form, so fluency here is what makes parallel and perpendicular a matter of looking.
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