A linear equation has infinitely many solutions
2x + 3y = 12 is satisfied by (6, 0), (0, 4), (3, 2) and by every other pair on one straight line. Solving it means describing that whole set, not finding "the" answer.
An equation in two unknowns has infinitely many solutions; plotting a few of them reveals the pattern. When the equation is linear, that pattern is a straight line, and two well-chosen points are enough to draw it.
Core ideas
In Linear Equations and Inequalities an equation in one unknown usually had one answer. The same sentence with a second unknown has endlessly many, and the graph is how you hold all of them at once.
2x + 3y = 12 is satisfied by (6, 0), (0, 4), (3, 2) and by every other pair on one straight line. Solving it means describing that whole set, not finding "the" answer.
Geometry says two distinct points fix a line, so two solutions suffice. Plot a third anyway: if it misses, one of the three is wrong, and you find out now rather than in “Slope”.
Setting y = 0 and then x = 0 each collapses the equation to one unknown, which is the case Linear Equations and Inequalities already solved. No other pair of points is easier to get.
The material
A table always works. Intercepts are faster. Two shapes are special.
An equation that can be written ax + by = c with a and b not both zero. Its graph is a straight line, and every straight line is the graph of such an equation.
The word linear earns its name here rather than in Linear Equations and Inequalities: what is straight is the graph. The defining feature on the algebra side is that x and y each appear to the first power only, never multiplied together, never inside a root or a denominator. xy = 6 and y = x² are equations in two variables that are not linear, and their graphs are not lines.
Choose a value for x, substitute, solve the resulting one-unknown equation for y, and record the pair. Repeat. This never fails and needs no new technique, which makes it the method to fall back on whenever a shortcut is not available or not remembered.
Four points, and they fall in a line: each step of one to the right drops y by two. That constant drop is the subject of “Slope”.
The x-intercept is where the graph meets the x-axis, found by setting y = 0. The y-intercept is where it meets the y-axis, found by setting x = 0.
The rule is easy to state backwards, so anchor it to the picture: every point on the x-axis has y = 0, so to land on the x-axis you impose y = 0. The intercept you get is an x-value.
Set y = 0: 2x = 12, so x = 6 and the x-intercept is (6, 0). Set x = 0: 3y = 12, so y = 4 and the y-intercept is (0, 4). Check with a third: (3, 2) gives 6 + 6 = 12, true.
The method degrades gracefully rather than failing. A line through the origin has both intercepts at (0, 0) — one point, not two — so you take a second point from a table instead.
When one of the coefficients is zero the equation loses a variable, and the graph is a line parallel to an axis:
Both are genuine linear equations under the definition above: x = a is 1·x + 0·y = a. The instinct that x = −2 should be a single point comes from Linear Equations and Inequalities, where it was one; with a second variable present, y is unconstrained and the solution set is a whole line.
Keep x = −2 in view. It is the one shape that will fail the test in “What a Function Is”, and knowing what it looks like now is what makes that test obvious later.
Interactive
Two points, the line through them, and what it crosses
Method
Intercepts first, table as the fallback, third point always.
If only x appears the line is vertical; if only y, horizontal. Draw it and stop — no table is needed.
This is a one-unknown equation of the kind Linear Equations and Inequalities handled. The result is the x-intercept (x, 0).
Same again, giving (0, y). If both intercepts came out at the origin, pick any other x and get a second point from the equation.
Any convenient x. If the three are not in a line, recheck the arithmetic before drawing anything; a ruler laid across two correct points and one wrong one hides the error.
Both intercepts, then a third point as the check.
The check point landing exactly midway is not luck. Equal steps in x produce equal steps in y on a line, which is the property “Slope” isolates and names. What it confirms is that the three points are collinear — consistent with each other — and not that any of them satisfies 2x + 3y = 12. Misread the constant as 24 and you get (12, 0), (0, 8) and (6, 4), which pass the midway check just as cleanly while every one of them is wrong for this equation. Correctness still rests on the substitutions: a third point can reveal an error, not certify its absence.
For a faded graph, start 3x − 2y = 12 with the supplied x-intercept (4, 0). Find the y-intercept, choose a third input that is not zero or four, verify all three pairs in the original equation, and only then draw the line. If the two intercepts collapse to one point on a different problem, state the table value you would use instead.
Given five equations including one vertical, one horizontal and one through the origin, you should produce a correct line for each and say which method you used and why. Recognising that the through-the-origin case defeats the intercept shortcut is the part that distinguishes a method from a memorised procedure.
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