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Lesson · Exponential and Logarithmic Functions · Applications

Compound Interest and Continuous Growth

Two formulas that look like conventions until they are built. A = P(1 + r/n)^(nt) is one multiplication repeated nt times, and A = P · e^(rt) is the value that expression settles down to as n grows. The second is “The Number e”'s limit with letters in it, and no new fact about money is involved.

A = P(1 + r/n)^(nt) n compoundings a year, over t years A = P · e^(rt) compounded continuously r is a DECIMAL per year: 5% → r = 0.05 = 1/20 $1000 at 5% for 10 yr: yearly 1628.89 monthly 1647.01 cont. 1648.72
Two formulas and what they pay

Core ideas

What this lesson establishes

One idea builds the first formula, one limit builds the second, and one habit of units keeps both of them right.

1

Each period multiplies, it does not add

One period at rate r/n turns P into P(1 + r/n). A second period multiplies by that same factor again. After nt periods the factor has been applied nt times, which is the entire derivation of A = P(1 + r/n)^(nt).

2

More frequent compounding converges, it does not explode

On $1000 at 5% for 10 years, moving from yearly to monthly gains $18.11; moving from monthly to continuous gains $1.71 more. The sequence increases with n but is bounded, and its limit is the continuous value.

3

The continuous formula is “The Number e”'s limit, relabelled

(1 + 1/m)^m → e. Put m = n/r, and (1 + r/n)^(nt) = [(1 + 1/m)^m]^(rt), which tends to e^(rt). e was not introduced for finance; finance is where the limit was first noticed.

The material

Where the two formulas come from

One repeated multiplication, one limit, and the units that make both of them wrong when they are wrong.

A principal P is invested at a nominal annual rate r, compounded n times a year, for t years. Every quantity in that sentence has a unit attached, and most errors with these formulas are unit errors rather than algebra errors.

Definition · Nominal rate

The nominal annual rate r is quoted per year and split evenly among the n periods, so one period carries the rate r/n. A nominal 5% compounded monthly means 5/12 of a percent a month. It is a name for twelve times the monthly rate, not the growth actually achieved over a year.

The first formula is a repeated multiplication and nothing more. Each period multiplies the balance by 1 + r/n, so the balances form a geometric sequence.

after 1 period P(1 + r/n) after 2 periods P(1 + r/n)² after k periods P(1 + r/n)^k t years is nt periods, so A = P(1 + r/n)^(nt)
Definition · Effective annual rate

The effective annual rate is (1 + r/n)^n − 1: the single yearly rate that would produce the same balance after one year. For a nominal 5% compounded monthly it is (1 + 0.05/12)^12 − 1 ≈ 0.051162, that is 5.1162%. Two accounts quoted at different frequencies can only be compared through this number.

Now increase n and watch. The numbers below are $1000 at a nominal 5% for 10 years, each rounded to the nearest cent.

n = 1 yearly 1000(1.05)^10 = 1628.89 n = 2 half-yearly 1000(1.025)^20 = 1638.62 n = 4 quarterly 1000(1.0125)^40 = 1643.62 n = 12 monthly 1000(1 + 0.05/12)^120 = 1647.01 n = 365 daily 1000(1 + 0.05/365)^3650 = 1648.66 n → ∞ continuous 1000 · e^0.5 = 1648.72 simple interest, for scale 1000(1 + 0.05 · 10) = 1500.00

The column climbs and then stops climbing. Daily and continuous differ by about six cents over ten years on a thousand dollars. "Compounded continuously" is not a claim about speed — it is the ceiling of the process, and the last few frequencies are already sitting against it.

Theorem · The continuous limit

As n → ∞, P(1 + r/n)^(nt) → P · e^(rt).

Substitute m = n/r, so that r/n = 1/m and nt = m · rt. The expression becomes P[(1 + 1/m)^m]^(rt), and m → ∞ as n → ∞. The inner bracket tends to e by “The Number e”, so the whole expression tends to P · e^(rt).

Solving for the other letters

P and A come out by dividing. r and t sit in the exponent, so they need “Solving Exponential Equations”. To double a balance under continuous growth, set 2P = P · e^(rt); the P cancels, 2 = e^(rt), and rt = ln 2, so t = ln 2 / r.

That the principal cancels is the characteristic property of exponential growth from “Growth and Decay”: the time to double does not depend on where you start. At 5% continuous it is ln 2 / 0.05 ≈ 13.86 years, and compounded yearly instead it is ln 2 / ln(1.05) ≈ 14.21 years.

The banker's shortcut follows from ln 2 ≈ 0.6931. Doubling time is roughly 70 divided by the rate as a percent, which at 5% gives 14 years against a true 13.86. It is an approximation of a logarithm, and it drifts at large rates: at 20% the rule says 3.5 years and the continuous answer is 3.47, but at 100% it says 0.7 and the answer is 0.69.

Example · What a percent sign costs

Entering 5 instead of 0.05 for a monthly-compounded account makes the monthly factor 1 + 5/12, a rate of 500% a year. Over ten years $1000 becomes about 1.4 · 10^21 dollars. The formula reports it without complaint, because nothing in the algebra knows what a percent is.

Interactive

Compounding

Six frequencies against the continuous limit

Exponential
yearlymonthlycontinuoussimple interest

Method

Using the compound interest formula

Four steps, and two of them are about units rather than algebra.

1

Convert the rate to a decimal per year

5% is 0.05. Entered as 5 it is a rate of 500%, and every later step will run perfectly and return a number that is wrong by a factor of billions.

2

Count periods, not years

n is periods per year and t is years, so the exponent is their product. Quarterly for five years is 20 periods — not 5, and not 4.

3

Build the base, then raise it once

Keep 1 + r/n exact if you can: 1 + 0.06/4 = 1.015, while 1 + 0.05/12 = 1 + 1/240 should stay in that exact form rather than be replaced by a truncated decimal. Rounding the base before raising it to the 120th power moves the error up into the dollars.

4

Compare accounts by effective annual rate

(1 + r/n)^n − 1 for periodic compounding, e^r − 1 for continuous. Two nominal rates quoted at different frequencies cannot be compared as they stand.

Rates, periods and limits

Score 0 / 0

$1000 at a nominal 6% for 5 years, compounded quarterly

Four numbers go in. The only thinking is which of them belongs where.

P = 1000 r = 6/100 = 0.06 n = 4 t = 5 r/n = 0.06/4 = 0.015 the rate for ONE quarter n · t = 4 · 5 = 20 the number of quarters A = 1000(1 + 0.015)^20 = 1000(1.015)^20 ≈ 1346.86 to the nearest cent for comparison: yearly 1000(1.06)^5 ≈ 1338.23 continuous 1000 · e^(0.30) ≈ 1349.86 effective annual rate (1.015)^4 − 1 ≈ 0.061364 = 6.1364%

Quarterly beats yearly by $8.63 and loses to continuous by $3.00. Both gaps are small next to the $346.86 of interest itself, which is the honest summary of compounding frequency: it matters, and it matters far less than the rate and the term.

The effective rate is what makes the account comparable with anything else. A flat 6.1% paid once a year sounds better than 6%, and it is not: 6% compounded quarterly earns 6.1364% a year.

For a faded model, take $1500 at a nominal 4.8% compounded monthly for two years. The period rate 0.048/12 and period count 24 are supplied. Assemble the periodic formula without truncating the base, compute once at the end, and compare it with the continuous expression 1500·e^(0.048·2). Check that both exceed the simple-interest amount and that the periodic value stays below the continuous ceiling.

Common mistakes

1
Entering the rate as a percent5 instead of 0.05 makes the monthly factor 1 + 5/12 and turns $1000 into about 1.4 · 10^21 dollars over ten years. Nothing in the formula can detect it, because a formula does not know that r was meant to be a proportion.
2
Using t where nt belongsQuarterly for five years is 20 compoundings. 1000(1.015)^5 prices five quarters — fifteen months — and comes to $1077.28 against the correct $1346.86. The exponent is periods, and the periods are n · t.
3
Comparing two nominal rates directly6% compounded monthly and 6.1% compounded yearly do not rank the way the quoted numbers do. The first has effective rate (1 + 0.06/12)^12 − 1 ≈ 6.1678%, so it is the better of the two. Convert both to effective rates and then compare.

Check your understanding

✓
Finish when you can build the formula instead of recalling it.

Asked for a monthly-compounded balance, you should be able to write 1 + r/12 for one month and 12t for the number of months, and assemble A = P(1 + r/12)^(12t) from those two facts alone. A recalled formula with n and t in the wrong places looks exactly like a correct one until the money is wrong.

Note: e entered this course in “The Number e” as the limit of (1 + 1/n)^n, with no application attached to it. This is the application, and it is also the historical order: the limit was first met by asking what happens to an account compounded more and more often.

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